Question

8 men and 12 boys can do a piece of work in 10 days while 6 men and 8 boys can do the same work in 14 days. Find the time taken by a single man and a single bou to do the same work

Answer 1

Answer:

Hey mate...

Here's ur answer :

Let, x = time taken by men to do the same work

and y = time taken by boy to do the same work .

.°. Equations are

8x+12y = 10 ------(1)

& 6x+8y = 14------(2)

Multiply eqn (1) by 2 and eqn (2) by 3.

we get,

16x+24y = 20-----(3)

& 18x+24y = 42-----(4)

Now, Subtract eqn (3) from (4)

18x+24y = 42

–

16x+24y = 20

—————————

2x = 22

.°. x = 11

put value of x in eqn (2)

.°. 8y = 14 - 66

y = -52/8

y= -6.5

but time can not be negative

hence, y = 6.5

Ans: Therefore, the the time taken by a men is 11 days and a boy is 6.5 days.

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