8 men and 12 boys can finish a piece of work in 10 days while 6 men and 8 boys can finish it in 14 days find the time taken by one man alone and one baby alone to finish it
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Step-by-step explanation:
(8m+12b) 10 = (6m+8b) 14
80m+120b = 84m+112b
120b-112b=84m- 80m
8b=4m
2b=1m. (1-men = 2-baby)
→8m+12b = 10 days
16b+12b =10 days
28 boys = 10 days
1man+1baby= 2 baby +1 baby
3 baby × X =28×10
X= 28×10/3
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