Question

. 8 men and 12 boys can finish a piece of work in 10 days. While 6 men and 8
boys can finish it in 14 days. Find the time taken by one man alone and that
by one boy alone to finish the work.​

Answer 1

Answer:

Step-by-step explanation:

Suppose,one man and boy doing work above xdays and y days .

8x+12y=10

6x+8y=14

That you can solve that by comparing to ax+by=c

Answer 2

$\huge{\bold{\underline{\underline{answer}}}}$

let 1 man finish the work in 'x' days and

1 boy finish the work in 'y' days

when 1 man work complete work in 'x' days

then 8 man work in

$\frac{8}{x} days$

when 1 boy complete work in 'y' days

then 12 boy complete work in

$\frac{12}{y} days$

our equation is:-

$\frac{8}{x} + \frac{12}{y} = \frac{1}{10}$

similarly, in second case

$\frac{6}{x} + \frac{8}{y} = \frac{1}{14}$

$let \: \frac{1}{x} to \: be \: \bold{ a }\: and \: \frac{1}{y} to \: be \: \bold{b} \\ so \: that \\ 8a + 12b = \frac{1}{10} \\ \\ => 80a + 120b = 1...... {eq}^{n} 1$

$6a + 8b = \frac{1}{14} \\ 84a + 112b = 1..... {eq}^{n} 2 \\ \: after \: elimination \: u \: will \: get \: values \: of \: x \: and \: y \: which\: are \: ur \: answer. \\ hope \: it \: helps \: u....$