Math, asked by krishanant10108, 7 months ago

8 men and 12 boys can finish a piece of work in 5 days, while 6 men and 8 boys can finish it in 7 days Find the
time taken by 1 man alone and that by 1 boy alone to finish the work.
Answer:

Answers

Answered by Anonymous
0

Answer:

Suppose 1 man alone can finish the work in x days and 1 boy alone can finish it in y days. <br> Then , 1 man's 1 day's work =

. <br> And, 1 boy's 1 day's work =

<br> 8 men and 12 boys can finish the work in 5 days <br>

( 8 men's 1 day's work ) + ( 12 boy's 1 day's work ) =

<br>

<br>

... (i), where

<br> Again, 6 men and 8 boys can finish the work in 7 days <br>

( 6 men's 1 day's work) + ( 8 boy's 1 day's work)

<br>

<br>

... (ii) <br> On multiplying (i) by 3, (ii) by 4 and subtracting the results, we get <br>

<br> On putting

in (ii), we get <br>

<br>

<br>

one man along can finish the work in 70 days, <br> and one boy alone can finish the work in 140 days.

Answered by kjjio
0

Answer:

Suppose 1 man alone can finish the work in x days and 1 boy alone can finish it in y days. <br> Then , 1 man's 1 day's work =

. <br> And, 1 boy's 1 day's work =

<br> 8 men and 12 boys can finish the work in 5 days <br>

( 8 men's 1 day's work ) + ( 12 boy's 1 day's work ) =

<br>

<br>

... (i), where

<br> Again, 6 men and 8 boys can finish the work in 7 days <br>

( 6 men's 1 day's work) + ( 8 boy's 1 day's work)

<br>

<br>

... (ii) <br> On multiplying (i) by 3, (ii) by 4 and subtracting the results, we get <br>

<br> On putting

in (ii), we get <br>

<br>

<br>

one man along can finish the work in 70 days, <br> and one boy alone can finish the work in 140 days.

Step-by-step explanation:

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