8 men and 12 boys can finish a work in 10 days while 6 men and 8 boys can finish it in 14 day.Find the time taken by one màn and one boy alone to finish the work.
Answers
One man alone can finish the work in 140 days and one boy alone can finish the work in 280 days.
Step-by-step explanation:
Given:
Here 8 men and 12 boys can finish a work in 10 days while 6 men and 8 boys can finish it in 14 day.
Suppose that one man alone can finish the work in x days and one boy alone can finish it in y days. Then,
One man's one day's work =
One boy's one day's work =
∴ Eight men's one day's work =
12 boy's one day's work =
Since 8 men and 12 boys can finish the work in 10 days,
⇒ [1]
Again, 6 men and 8 boys can finish the work in 14 days.
⇒ [2]
Putting and in equations (1) and (2), we get
80u + 120v − 1 = 0
84u + 112v - 1 = 0
By using cross-multiplication method, we have
And
Now Substituting , we get
Thus, one man alone can finish the work in 140 days and one boy alone can finish the work in 280 days
Dear Student,
◆ Answer -
93.33 days
● Explanation -
Let x and y be part of the work 1 man and 1 boy can finish in 1 day respectively.
8x + 12y = 1/10 ...(1)
6x + 8y = 1/14 ...(2)
Solving (1) & (2),
x = 1/140
y = 1/280
So the days taken by 1 man and 1 boy alone to complete the work -
1/140 + 1/280 = 1/t
3/280 = 1/t
1/t = 3/280
t = 93.33 days
Hence, 93.33 days taken by 1 man and 1 boy alone to complete the work.
Thanks dear. Hope this helps you...