8 men and 12 women can finish a piece of work in 5 days , while 6 men and 8 woman can finish it in 7 day. Find the time taken by 1 man alone and that 1 woman alone to finish the work.
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(8m + 12w)×5 =(6m +8w)×7
40m +50w=42m+56w
6w=2m
m:w=3:1
so total work is
(8×3 +12×1)×5
36×5 =180
so 1×3 + 1×1 =4
or days required = 36×5/4=9×5=45days
40m +50w=42m+56w
6w=2m
m:w=3:1
so total work is
(8×3 +12×1)×5
36×5 =180
so 1×3 + 1×1 =4
or days required = 36×5/4=9×5=45days
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