8 mL of a solution of NaOH is found to be completely neutralised by 10mL of a given solution of HCl. If we take 4 mL of the same solution of NaOH , the amount of HCl solution (the same solution as before) required to neutralise it will be
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If we take 20 mL of the same solution of NaOH, the amount HCl solution (the same solution as before) required to neutralise it will be. 10 mL of NaOH will require HCl = 8 mL and 20 mL of NaOH will require HCl= 16 mL.
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