Question

8. MOTION
109
reach there?
La stone is thrown in vertically upward direction with a velocity of 5 ms, the
acceleration of the stone during its motion is 10 ms in the downward direction.
What will be the height attained by the stone and how much time will it take to​

Answer 1

Answer:

Given, initial velocity, u=5ms

−1

Final velocity, v=0

Since, u is upward & a is downward, it is a retarded motion.

∴a=−10ms

−2

Height attained by stone, s=?

Time take to attain height, t=?

(i) Using the relation, v

2

−u

2

=2as, we have

s=v

2

−u

2

/2a

=(0)

2

−(5)

2

/2×(−10)=1.25m

(ii) Using the relation, v=u+at

0=5+(−10)t or

t=5/10=0.5s