8.
nth term of 1+ (1+2) + (1+2+3)+........... (1+2+3+...+n) is
n(n+1)
3) n(n+1)
2) n° (n+1)
4) n²
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Answer:
n^th terms =(1+2+3+4....n^th ) ~n*(n+1)/2
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