8. Numbers entered into a cell are automatically
aligned
9. If A1:A5 contain the number 16, 10, 3, 25 and 6 then = Average(A1:A5;60) will display
10. In
referencing, the reference changes rows and columns autom
is copi
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Answer:{Answer} Answer :- area of square is given that= 6084sq m.
Answer:{Answer} Answer :- area of square is given that= 6084sq m.= fine:-
Answer:{Answer} Answer :- area of square is given that= 6084sq m.= fine:-area of square= (sides)²
Answer:{Answer} Answer :- area of square is given that= 6084sq m.= fine:-area of square= (sides)²√6084= 78m
Answer:{Answer} Answer :- area of square is given that= 6084sq m.= fine:-area of square= (sides)²√6084= 78mnow for finding it the length of wire which can go along the boundary of the plot, we have to find the perimeter of the square plot.
Answer:{Answer} Answer :- area of square is given that= 6084sq m.= fine:-area of square= (sides)²√6084= 78mnow for finding it the length of wire which can go along the boundary of the plot, we have to find the perimeter of the square plot.so,
Answer:{Answer} Answer :- area of square is given that= 6084sq m.= fine:-area of square= (sides)²√6084= 78mnow for finding it the length of wire which can go along the boundary of the plot, we have to find the perimeter of the square plot.so,perimeter of square plot
Answer:{Answer} Answer :- area of square is given that= 6084sq m.= fine:-area of square= (sides)²√6084= 78mnow for finding it the length of wire which can go along the boundary of the plot, we have to find the perimeter of the square plot.so,perimeter of square plot= 4×side
Answer:{Answer} Answer :- area of square is given that= 6084sq m.= fine:-area of square= (sides)²√6084= 78mnow for finding it the length of wire which can go along the boundary of the plot, we have to find the perimeter of the square plot.so,perimeter of square plot= 4×side= 4×78
Answer:{Answer} Answer :- area of square is given that= 6084sq m.= fine:-area of square= (sides)²√6084= 78mnow for finding it the length of wire which can go along the boundary of the plot, we have to find the perimeter of the square plot.so,perimeter of square plot= 4×side= 4×78perimeter of square = 312 m
Answer:{Answer} Answer :- area of square is given that= 6084sq m.= fine:-area of square= (sides)²√6084= 78mnow for finding it the length of wire which can go along the boundary of the plot, we have to find the perimeter of the square plot.so,perimeter of square plot= 4×side= 4×78perimeter of square = 312 mnow,
Answer:{Answer} Answer :- area of square is given that= 6084sq m.= fine:-area of square= (sides)²√6084= 78mnow for finding it the length of wire which can go along the boundary of the plot, we have to find the perimeter of the square plot.so,perimeter of square plot= 4×side= 4×78perimeter of square = 312 mnow,the length of four rounds of wire= 312×4= 1248m²
Answer:{Answer} Answer :- area of square is given that= 6084sq m.= fine:-area of square= (sides)²√6084= 78mnow for finding it the length of wire which can go along the boundary of the plot, we have to find the perimeter of the square plot.so,perimeter of square plot= 4×side= 4×78perimeter of square = 312 mnow,the length of four rounds of wire= 312×4= 1248m²so, the length of four rounds of wire is 1248m²
Answer:{Answer} Answer :- area of square is given that= 6084sq m.= fine:-area of square= (sides)²√6084= 78mnow for finding it the length of wire which can go along the boundary of the plot, we have to find the perimeter of the square plot.so,perimeter of square plot= 4×side= 4×78perimeter of square = 312 mnow,the length of four rounds of wire= 312×4= 1248m²so, the length of four rounds of wire is 1248m²
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