8 ohm resistance wire is stretched to double its length calculate the new resistance
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New resistance will be 32 ohms
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Since resistance is 8ohm thus
It is given the length is stretched to be double so the area of crossection will become half so 8ohm=2l/1/2area which is equal to 4 times the old resistance that is 8x4=32
Thanks for your time
It is given the length is stretched to be double so the area of crossection will become half so 8ohm=2l/1/2area which is equal to 4 times the old resistance that is 8x4=32
Thanks for your time
riditanand25:
Good answer
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