Question

8. On temperature scale Y, water freezes at -160° Y and boils at -50°Y. On this Y scale, a temperature of 340 K is 1. -106.30 Y 2. -96.3°Y 3. -86.3°Y 4. -76.3°Y​

Answer 1

Answer:

3. -86.3

Explanation:

Water boils at at 100C or 373K or -50Y and freezes at 0C or 273K or -160Y

now make two equations out of this statement:-

$273x + y = - 160$

$373x + y = - 50$

Solve for x and y

you will get x=1.1 & y= -460.3

Now solve for 340K

i.e. 340*1.1 - 460.3= -86.3

Answer 2

Answer:

3.-86.3

Explanation:

water boils at 100c or 373k or -50y and freezes at oc or 273k or -160y

now make two equations out of this statement :-

273x+y = -160

373x+-y = -50

solve for x and y

you will get x=1.18y= -460.3

Now solve for 340k

i.e 340* 1.1-460.3=- 86.3