Question

8. One out of two numbers is thrice the other. If their sum is 124. find the numbers.
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Answer 1

Step-by-step explanation:

Le the numbers be x 'nd y respectively.

Assuming that we'll make the playing constant as x, we'll continue the experiment with x.

So, let us assume x = 3y.

That means x>y. [Important Conclusion]

Can we move on further?

We have now, the 2nd statement :-

The sum of the numbers is 24.

Now, we'll substitute 'em according to the assumptions.

x + y = 124

3y + y = 124

4y = 124

y = $\rm{\dfrac{124}{4}}$

So, we have, y = 31.

Now, we'd assumed x as 3y.

Substitute again!

3y = 3*31

So, we've x = 93 as the answer.

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Verify it :-

93 + 31 = 124, hence verified!

Answer 2

Answer:

${ \large{ \pmb{ \sf{★ Given... }}}}$

One out of two numbers is thrice the other.

Sum of the numbers = 124

${ \large{ \pmb{ \sf{★ To \: Find... }}}}$

The numbers..?

${ \large{ \pmb{ \sf{★Assume \: That... }}}}$

One number = x

second number is thrice of first number,

Second number = 3x

${ \large{ \pmb{ \sf{★Solution... }}}}$

According to question, their sum = 124

$: { \implies{ \sf{3x + x = 124}}}$

$\: : { \implies{ \sf{4x = 124}}}$

$\: : { \implies{ \sf{x = \frac{124}{4} }}}$

$\: : { \implies{ \bf{x = 31}}}$

${ \large{ \pmb{ \sf{★Finding \: Numbers... }}}}$

: ➙ First Number = x = 31

: ➙ Second Number = 3x = 3(31) = 93

${ \therefore{ \sf{ \blue{The \: required \: numbers \: are \: 93, 31 </p><p>}}}}$