Physics, asked by Priyanshukumasingh, 9 months ago

8 : Ou kon) hay
An object is druped from
Mest at
a height of 150m
and at the same
time anather objectisdruped
from west aut a height of toom
What is the difference in there height
2sec later ifboth the object druped with same acceleration how does difference in height very with time​

Answers

Answered by abhinav979verma
1

Explanation:

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Answered by sshailshetty
0

Answer:

for Ist object. u =0. t=2sec

the object is 150m abobe the ground

a =g= 10 (9.8)

s=ut+1/2at^2

s=0×2+1/2×10×2×2

s=20

AFTER 2SECOND THE DISTANCE BETWEEN OBJECT AND GROUND IS. 150-20=130M

for IInd object. u =0. t=2sec

a =g= 10 (9.8)

the object is 100m abobe the ground

a =g= 10 (9.8)

s=ut+1/2at^2

s=0×2+1/2×10×2×2

s=20

AFTER 2SECOND THE DISTANCE BETWEEN OBJECT AND GROUND IS. 100-20=80M

THE DISTANCE BETWEEN THE OBJECTS AFTER 2 SEC

===130-80=50

Explanation:

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