Question

8. Parveen wanted to make a temporary shelter for her car, by making a box-like structure
with tarpaulin that covers all the four sides and the top of the car (with the front face
as a flap which can be rolled up). Assuming that the stitching margins are very small,
and therefore negligible, how much tarpaulin would be required to make the shelter of
height 2.5 m, with base dimensions 4 m x 3 m?​

Answer 1

Here, length (l) = 4 m,

breadth (b) = 3m

and height (h) = 2.5 m

The structure is like a cuboid.

∴ The surface area of the cuboid, excluding the base

=[Lateral surface area] + [Area of ceiling]

= [2(l + b)h] + [lb]

= [2(4 + 3) x 2.5] m2 + [4 x 3] m2

= 35 m2 + 12 m2 = 47 m2

Thus, 47 m2 tarpaulin would be required.

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