Question

8. Parveen wanted to make a temporary shelter for her car, by making a box-like structure
with tarpaulin that covers all the four sides and the top of the car (with the front face
as a flap which can be rolled up). Assuming that the stitching margins are very small,
and therefore negligible, how much tarpaulin would be required to make the shelter of
height 2.5 m, with base dimensions 4 mx 3 m?​

Answer 1

Answer:

47$m^{2}$ of tarpaulin is required.

Step-by-step explanation:

Length of shelter = 4 m

Breadth of shelter = 3 m

Height of shelter = 2.5 m

To find the area of the shelter which is in cuboid shape as the bottom is uncovered

area of the total tarpaulin required = area of cuboid - area of bottom

area of cuboid = 2(lb + bh + lh)  

area of bottom = l x b

area of total tarpaulin required = 2(lb + bh + lh) - lb

                                                   = 2(lb) + 2(bh) + 2(lh) - lb

                                                   = 2bh + 2lh + lb

                                                   =  lb + 2(bh) + 2(lh)

                                                   = 4 x 3 + 2(3 x 2.5) + 2(4 x 2.5)

                                                   = 12 + 2(7.5) + 2(10)

                                                   = 12 + 15 + 20

                                                   = 47$m^{2}$

Therefore 47$m^{2}$ of tarpaulin is required.

HOPE THIS HELPS YOU

HAVE A NICE DAY :)

Answer 2

Step-by-step explanation:

Solution :-

Dimension of the non-like structure = 4m×3m×2.5m

Tarpaulin only required for all the

for sides and top.

Thus Tarpaulin required = 2(l+b)×h+lb

=[2(4+3)×2.5+4×3]m

2

=[35+12]m

2

=47m

2