Question

8 pipes are required to fill a tank in 1hr 20min. How long will it take if only 6 pipes of the same type are used?

Answer 1

Answer:

ANSWER

Let the desired time to fill the tank be x minutes.

In 80 mins a tank is filled by 6 pipes

Lesser the number of pipes more will be the time required by it to fill the tank.

So, this is a case of inverse proportion.

Hence, 80×6=x×5

⇒

5

80×6

=x

⇒x=96

Thus, the time is taken to fill the tank by 5 pipes is 96 minutes or 1 hour 36 minutes.