Math, asked by mukeshyadavs492, 1 year ago

8 plus 2 root 15 ka whole root


smishra97: √5 + √3

Answers

Answered by abhi569
1

 \sqrt{8 + 2 \sqrt{15} }  \\  \\   \sqrt{3 + 5 +( 2 \sqrt{3 \times 5}) }  \\  \\  \sqrt{ (\sqrt{3}  )^{2} +  (\sqrt{5}) ^{2}   + (2 \sqrt{3 \times 5} )}  \\  \\  \\  \\  \\ by \: formula \:  {(a + b)}^{2}  =  {a}^{2}  +  {b}^{2}  + 2ab \\  \\  \\  \\ here \\  \\  \sqrt{( \sqrt{3} ) ^{2}  +  ({ \sqrt{5} )}^{2}  + (2 \sqrt{3 \times 5} )}  \\  \\  \sqrt{( \sqrt{3}  +  \sqrt{5}) ^{2}  }  \\  \\ ( \sqrt{3}  +  \sqrt{5}  ) ^{2 \times  \frac{1}{2} }  \\  \\  \sqrt{3}  +  \sqrt{5}




I hope this will help you


(-:
Answered by PADMINI
0
5+3+2root(5*3)
(root5)^2+(root3)^2+2root5*root3
(root5+root3)^2
so
root(5+root3)^2
root5+root3
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