Question

8. PQRS is a trapezium as shown in the figure such that PQ|| SR and SP 1 PQ.
Find the area of trapezium PQRS, if PQ-15 m, SQ=17 m and SR = 11 m.​

Answer 1

Answer:

From R draw RT perpendicular PQ

∴,SR=PT=20cm

TQ=PT−PQ=29−20=9cm

In △TQR,∠T=90

∘

By using Pythagoras theorem we have

RT

2

=RQ

2

−TQ

2

=15

2

−9

2

=225−81=144

⇒RT=12units

SP=RT=12cm

∴,PTRS is a rectangle

Area of trapezium PQRS=Area of rectangle PTRS+area of triangleTQR

=PT×RT+

2

1

×TQ×RT

=12×20+

2

1

×9×12

=240+54=294sq.cms

∴ Area of trapezium PQRS=294sq.cms