Question

8. Product of zeroes of x'+7x+10-​

Answer 1

Step-by-step explanation:

Let p(x) = x ^ 2 + 7x + 10 Zero of the polynomial is the value of x where p(x) = 0 Putting p(x) = 0 x ^ 2 + 7x + 10 = 0 We find roots using splitting the middle term method x ^ 2 + 2x + 5x + 10 = 0 x(x + 2) + 5(x + 2) = 0 (x + 2)(x + 5) = 0 Sox = - 2, - 5 Therefore, Splitting the middle term method We need to find two numbers whose Sum = 7 Product epsilon*t = 10 * 1 = 10 1 and 6 2 and 5 Sum Product 7 7 10 alpha=-2 8 B=-5 are the zeroes of polynomial

therefore 5 zeroes of polynomial