Question

8.Prove that 12 n cannot end with digit 0 or 5 for any natural number ‘n’.

Answer 1

$\huge{\mathfrak{Answer:-}}$

_____________________________

For any number ${m^{n}}$ to end with 0 or 5, it must have both 2 and 5 in it's prime factorization

But,

$\red{\fbox{12=2^{2}\times 3}}$

It doesn't have 5 in it's prime factorization. Hence, ${12^{n}}$ doesn't end with zero.

____________________________

Cheers,

Nandini✌❤