Question

8. Prove that the diagonals of a square divide it into
four congruent triangles.

90 degree​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Let ABCD be the square and line AC be its diagonal. We know, in a square all sides are equal and all the angles are right angled.

So, in ∆ABC and ∆ACD,

AB=CD

$\angle ABC= \angle ACD$

AD=BC

So, by SAS congurency both the triangles are equal.

NOW,

In ∆AOD and∆DOC

DO=DO(common)

DC=AD

$\angle AOD=\angle DOC$

∆AOD =~∆DOC