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1. resistance in arm C E = R1+R2 = 5+4 = 9 ohm
2 given
resistance in arm AB = R1 + R2 = 6+3 = 9 ohm
potential difference (v) = 4.5
we know
V=I×R
I(current)= V ( potential difference) / R ( resistance )
I = 4.5/9 = 0.5 ampere
3. I = 0.5
resistance R = 4 ohm
V potential difference = I×R
0.5 × 4= 2 V
2 given
resistance in arm AB = R1 + R2 = 6+3 = 9 ohm
potential difference (v) = 4.5
we know
V=I×R
I(current)= V ( potential difference) / R ( resistance )
I = 4.5/9 = 0.5 ampere
3. I = 0.5
resistance R = 4 ohm
V potential difference = I×R
0.5 × 4= 2 V
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