Math, asked by jyoti3386, 3 months ago


8 Ramesh and Satish contested the election in the panchayat committee from their village. Ramesh
scored 11,484 votes which was 44% of the total votes. Satish scored 26% of the votes. Calculate
a the number of votes cast in the village, and
b the number of voters who did not vote for either Ramesh or Satish.​

Answers

Answered by SumedhaSen
11

Answer:

Total votes casted= 26100

Total voters who did not vote either to Ramesh and Satish is 7830

Step-by-step explanation:

Let X be the total voters.

Ramesh scored 44 % of X = 11484

44 X /100 = 11484

X = 11484 × 100/44

X = 26100.

Total no. of votes casted in the village is 26100

Now, Satish scored 26 % of 26100  

26 × 26100/100 = 678600/ 100 = 6786 voters.

Total votes casted to Satish and Ramesh= 11484+ 6786= 18270

Total votes casted= 26100

voters who did not vote either to Ramesh and satish= 26100-18270= 7830

Total voters who did not vote either to Ramesh and Satish is 7830

Answered by itzmysticalgirl1
10

Given ↓

Ramesh scored 11,484 votes which was 44% of the total votes. Satish scored 26% of the votes.

Solution ★

Let Total vote casTed be = x

44% of x = 11,484

x \times \frac{44}{100} = 11,484

x \times \frac{11,484×100}{44}

x \times \frac{1044×100}{44}

x = 26100

 Ans = 26100

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