Question

8) Ranbir bought a rectangular field of area 24000 square metres and
width 120 m. He wants to fence it with two rounds of wire. Find the length
of wire that will be required to fence the field.
​

Answer 1

Step-by-step explanation:

24000/120=200m is the length

hope it'll help you make it brainliest answer please please please

Answer 2

Given :

Area of rectangular field = 24000 m².

Width of rectangular field = 120 m

⠀⠀⠀⠀

To find :

Length of wire that will be required to fence the field?

⠀⠀⠀⠀

Solution:

⠀⠀⠀⠀

Let length of field be x m.

⠀⠀⠀⠀

$\bf{\dag}\;{\underline{\frak{As\;we\;know\;that,}}}$

$\star\;{\boxed{\sf{\pink{Area_{\;(rectangle)} = length \times breadth}}}}$

$:\implies\sf x \times 120 = 24000$

$:\implies\sf x = \cancel{ \dfrac{24000}{120}}$

$:\implies{\underline{\boxed{\frak{\purple{x = 200\;m}}}}}\;\bigstar$

$\therefore\:{\underline{\sf{Length\:of\;rectangular\;field\:is\: {\textsf{\textbf{200\;m}}}.}}}$

⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━━━⠀⠀⠀⠀

Now, Finding length of wire that will be required to fence the field.

⠀⠀⠀⠀

Length of wire required in one round = Perimeter of field

⠀⠀⠀⠀

$\star\;{\boxed{\sf{\pink{Perimeter_{\;(rectangle)} = 2(length + breadth)}}}}$

$:\implies\sf Perimeter_{\;(rectangle)} = 2(200 + 120)$

$:\implies\sf Perimeter_{\;(rectangle)} = 2 \times 320$

$:\implies{\underline{\boxed{\frak{\purple{Perimeter_{\;(rectangle)} = 640\;m}}}}}\;\bigstar$

$\therefore\:{\underline{\sf{Perimeter\:of\;rectangular\;field\:is\: {\textsf{\textbf{640\;m}}}.}}}$

⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━━━⠀⠀⠀⠀

Therefore,

⠀⠀⠀⠀

Length of wire required to fence the field in one round = 640 m

Length of wire required to fence the field in two round = 2 × 640 = 1280 m

⠀⠀⠀⠀

$\therefore\:{\underline{\sf{Hence,\:Total\:Length\:of\;wire\; required\:is\:{\textsf{\textbf{1280\;m}}}.}}}$