Math, asked by ashwinisakhare2407, 15 days ago

8. Ratio of present age of A & B is 2:3, present age of A is 24 yrs. After 4 yrs ratio of ages of B & C is 8: 5. Before 5 yrs ratio of ages of C & D was 4 : 7. After 17 years ratio of ages of D & E is 5:6. Find difference of ages of A & E at present. 1) 22 2) 19 3) 14 4) 17 5) None of these.​

Answers

Answered by kaurkawaldeep377
0

Answer:

The ratio of the ages of A and B, 8 years ago = 2x : 3x

According to the question

(2x + 4)/(3x + 4) = 5/7

⇒ 7 (2x + 4) = 5 (3x + 4)

⇒ 14x + 28 = 15x + 20

⇒ 15x – 14x = 28 – 20

⇒ x = 8

8 years ago-age of A = 2 × 8 = 16

8 years after-age of A = 16 + 8 + 8 = 32

8 years ago-age of B = 3 × 8 = 24

8 years after-age of B = 24 + 8 + 8 = 40

Ratio of ages of A to B after 8 years = 32 : 40 = 4 : 5

Short Trick:

Ratio of ages of A to B, 8 years ago = 2 : 3 or 4 : 6.

1 unit = 4 years

3 unit = 12 years

∴ Ratio of ages A to B, 8 years after = 4 : 5

Step-by-step explanation:

pls like and subscribe to my channel

Name= Noor__Gamer

Similar questions