Question

8. Sabtract (2a-3b+4c)from the sum of (a+3b-4c),(4a-b+9c)and
(2b+3c-a)? Need steps with ans
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Answer 1

Answer:

2a+b+12c

Explanation:

$(a + 3b + 4c) + (4a - b + 9c) + (2b + 3c - a) \\ (a + 4a - a) + (3b - b + 2b) + (4c + 9c + 3c) \\ (4a + 4b + 16c)$

Subtracting (2a-3b+4c) from (4a+4b+16c),

$(4a + 4b + 16c) - (2a - 3b + 4c) \\ 2a + b + 12c$