Question

8. Show that
1.2 23.
(1)
X +
- ...
3.45 4.5.6 5.6.7
1
{(6 + 6x + ) log (1 + X) - (6x + 3 }
+​

Answer 1

Answer:

Given equation is (2log9x)2-6(2log9x)+ 27log32=0. Let2log9x=y, we get y2-6y+8=0 ⇒y=4or 2. If 2log9x=22 ⇒log9x=2 ⇒x=81. If 2log9x=21

Missing: 3.45 ‎4.5.6 ‎5.6.7