Math, asked by babydoll06, 8 months ago

8. Show that:
(a) (2x - 7y)² + 28xy = 4x² + 49y²
(b) (a-b)(a+b) + (b-c)(b+c) + (c-a)(c+a) = 0​

Answers

Answered by sarbajitp68
3

Answer:

a) 4x² + 49y². b) 0

Step-by-step explanation:

a) (2x - 7y)² + 28xy = 4x² + 49y²

=)(2x - 7y)² + 28xy

=) (2x)² + (7y)² - 2(2x)(7y) + 28xy

=) 4x² + 49y² - 28xy + 28xy

=) 4x² + 49y².

b) (a-b)(a+b) + (b-c)(b+c) + (c-a)(c+a) = 0

=) a(a-b) + b(a-b) + b(b-c) + c(b-c) + c(c-a) + a(c-a)

=) a²- ab + ab - b² + b² - bc + bc - c² + c² - ac + ac - a²

=) a² - a² - ab + ab - b² + b² - bc + bc - c² + c² - ac + ac

=) Hence all eliminated and result is ZERO '0'

Answered by samuelbabu123456757
1

Answer:

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Step-by-step explanation:

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