Question

(8) sin (45° + 0) - cos (45° - 0) =
A. 2 cos 0 B. O C. 2 sin 0 D. 1​

Answer 1

Answer:

B . 0

Step-by-step explanation:

sin 45°=1/√2

cos 45°=1/√2

(1/√2) - (1/√2-0)

(1//√2) - ( 1/√2)

0

Answer 2

Step-by-step explanation:

USING FORMUALES ::--

SIN(A+B)= SINA COS B + COS A SIN B

COS(A-B) = COSA COS B - SINA SINB

SIN 0° =0 ,,,, SIN 45° = 1/√2

COS 0° =1 ,,,,,, COS 45° = 1/√2.

NOW , WE HAVE

SIN(45+0) - COS(45-0)

[ SIN 45° COS0° + COS45° SIN0°] — [COS45° COS0° – SIN45° SIN0°]

= [ 1/√2*1 + 1/√2*0 ] — [ 1/√2*1 – 1/√2 * 0]

= 1/√2 — 1/√2 =0

I HOPE IT HELPS U