Question

8.sin(90 + 0) =
a.cos Ob. -cos e
c.sino
d.- sin e​

Answer 1

Answer:

Sin(90° + θ)  =  Cosθ

Step-by-step explanation:

Sin(90° + θ)

Using Sin(A + B) = SInACosB + CosASinB

= Sin90°Cosθ + Cos90°Sinθ

Sin 90° = 1  & Cos90° = 0

= Cosθ

Sin(90° + θ)  =  Cosθ