Question

8. Solve for x and y if

Answer 1

In the attachments I have answered this problem.

The given matrrix equation is simplified and two quadratic equations are obtained by equating corresponding
elements on both sides.

I hope this answer helps you

Answer 2

Solution :

According to the problem given ,

Convert matrix form into algebraic

equations ,

i ) x² + 6x = -9

=> x² + 6x + 9 = 0

=> x² + 2 × x × 3 + 3² = 0

=> ( x + 3 )² = 0

Therefore ,

( x + 3 ) = 0 or ( x + 3 ) = 0

x = -3 or x = -3 ,

ii ) y² - 3y = 4

=> y² - 3y - 4 = 0

=> y² +1y - 4y - 4 = 0

=> y( y + 1 ) - 4(y + 1 ) = 0

=> (y+1)(y-4) = 0

y +1 = 0 or y - 4 = 0

y = -1 or y = 4

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