Question

8. Solve the differential equation
x^2 dy + y(x + y)dx = 0, given y = 1 when x = 1
(3)​

Answer 1

Answer:

x^2 dy + y(x + y)dx = 0

x^2 dy + yx dx + y^2 dx = 0

x^2 dy + (xy + y^2) dx = 0

dy/dx = -(xy + y^2) / x^2

put, y = vx

dy/dx = v + x dv/dx

..the continution is in photo..