8. Solve the following equations:
2x + 3y = 0
√3x + √2y=0
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9. Solve the following equations:
x + y = 10
x - y = 12
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Step-by-step explanation:
8) Given lines are 2x+3y=0
=>2x=-3y
=>x= -3y/2......(1)
and √3x+√2y=0....(2)
Substituting the value of x in (2) then
=>√3(-3y/2)+√2y=0
=>-3√3y/2+√2y=0
(-3√3y+2√2y)/2=0
=>y(2√2-3√3)=0
=>y=0
now from (1) x=-3(0)/2=0
The solution is (0,0)
9)
Given lines are x+y=10...(1)
and x-y=12....(2)
from (1)&(2)
x+y=10
x-y=12
---------
2x=22
--------
=>x=22/2=11
from (1) ,11+y=10=>y=10-11=-1
The values of x=11,y=-1
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