8. Solve: (x + 3)/6 + 1 = (6x – 1)/3
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X+3/6+1=(6x-1)/3
=3(X+3)=7(6x-1)
=3x+9=42x-7
=3x-42x=-7+9
=-39x=2
=X=-39/2
=X=18.5
=3(X+3)=7(6x-1)
=3x+9=42x-7
=3x-42x=-7+9
=-39x=2
=X=-39/2
=X=18.5
OK
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BY
I am answering ur question
let the digit at unit place be x and tens place=X+5. Original Number =10(x+5) with interchange of digits the new number =10x +(X+5). Therefore [original number] +[new number]=99 = 11x+50+11x+5=99=22x + 55=99=22x=99-55=22x=44= then X=2 that is unit digit and tens digit= X +5=2+5=7. Hence the original number = 72.....hope it helps
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