8 square -21x-9=0 find the roots by factorisation method
Answers
8 x² - 21 x - 9 = 0
==> 8 x² -24 x + 3 x - 9 = 0
==> 8 x ( x - 3 ) + 3 ( x - 3 ) = 0
==> ( x - 3 )( 8 x + 3 ) = 0
Either x - 3 = 0
==> x = 3
or : 8 x + 3 = 0
==> 8 x = -3
==> x = -3 / 8
Hope it helps
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Given,
p(x) = 8x^2 -21x-9=0
Now to solve a quadratic equation we can use 3 methods =>
1)Completing Square Method,
2)Middle term Split method, and
3)By Quadratic formula.
Here we will solve the equation by using the factorization method =>
8x^2 -21x-9=0
=>8x^2 -24x + 3x -9 =0
=> 8 x ( x - 3 ) + 3 ( x - 3 ) = 0
=> ( x - 3 )( 8 x + 3 ) = 0
Hence we have=>
Either x = 3 or x =-3/8
Extra information
In quadratic formula method =>
d = discriminant (decides the nature of roots or zeroes of a quadratic equation.
a)when d = 0
then the quadratic equation will have the same real and equal roots.
b)when d>0
then the quadratic equation will have two real and distinct roots.
c)when d<0
then the quadratic equation will have no real roots i.e it will have imaginary roots.