Question

8. Subtract a+b3+C3-3abc from
a3 + b3 +03+3abc
*​

Answer 1

Answer:

Step-by-step explanation:

If a + b + c = 0

Then,

a + b + c = 0

a + b = - c -- (I)

(a + b)^3 = (- c)^3

a^3 + b^3 + 3ab (a + b) = - c^3]

from equation (I) a + b = - c

a^3 + b^3 + 3ab (- c) = - c^3

a^3 + b^3 - 3abc = - c^3

a^3 + b^3 + c^3 = 3abc

Hence,

a^3 + b^3 + c^3 ‘not equal’ 0

but,

a^3 + b^3 + c^3 ‘equal’ 3abc

Answer 2

Answer:

6abc

Step-by-step explanation:

${a}^{3} + {b}^{3} + {c}^{3} + 3abc - ( {a}^{3} + {b}^{3} + {c}^{3} - 3abc)$

= a³ + b³ + c³ - (a³ + b³ + c³) + 3abc + 3abc

= 0 + 6abc

= 6abc

Answered by GauthMath.