Question

8. T ={x\x>0} U={x\*>1)​

Answer 1

Given, 

(x+1)dy=((x+1)2+y−3)dx

(1+x)dxdy=(x+1)2+y−3

dxdy=(x+1)+(x+1y−3)

dxdy−(1+x)1y=(1+x)−(1+x)3

I.F=e−∫1+x1dx=e−log(1+x)=1+x1

dxd(1+xy)=1−(1+x)23

1+xy=x+3(1+x)

hope it helps you

mark as brainest and follow