Question

8 tanA=15 then find sinA​

Answer 1

h = (p^2 + b^2)^(1/2) = (15^2 + 8^2)^(1/2) = 17
SinA = 15/17

Answer 2

Answer:

Step-by-step explanation:

Tan 'a'= 15/8=perpendicular(P)/base(B)

sin'a'=perpendicular/hypotenuse

cos'a'=Base/hypotenuse(H)

(H)²=(P)²+(B)²

(H)²=(15)²+(8)²

(H)²=225+64

(H)²=289

H=17

sin'a'=15/17

cos'a'=8/17

 sin'a'-cos'a'=15/17-8/17

 15-8/17

 =7/17