Question

8 taps can fill a tank in 27 minutes with the same rate of flow. If three taps go out of order, how long will the remaining taps take to fill the tank?​

Answer 1

$\sf \large Given,$

$\sf \to 8\;taps\;fill\;a\;tank\;in\;27\;minutes.$

$\sf \to 3\;taps\;go\;out\;of\;order!!$

$\sf \large So,$

$\sf \to Time\;taken\;to\;fill\;a\;tank\;with\;8\;taps=27\;minutes$

$\sf \to Time\;taken\;to\;fill\;a\;tank\;with\;1\;tap=27\times{8}=216\;minutes$

$\sf \to 3\;taps\;go\;out\;of\;order.$

$\sf \to Taps\;remaining=8-3=5$

$\sf \large Now,$

$\sf \to Time\;taken\;to\;fill\;a\;tank\;with\;5\;taps=\frac{216}{5}$

$\sf \bigstar Time\;taken\;to\;fill\;a\;tank\;with\;5\;taps=43.2\;minutes$