Question

8 taps can fill a tank in 27 minutes with the same rate of follow if three taps go out for order how long will remain tab take to fill the tank

Answer 1

$143 { { \frac{ { \frac{xx { \frac{ \sqrt{g \gamma log( \cot( \tan( \alpha log( \sec(\pi \binom{ log( \gamma \beta \beta \alpha \cos( \sin( ln( log( \sec(\pi \beta \sec( \binom{\%\%e}{?} ) ) ) ) ) ) ) }{?} ) ) ) ) ) } }{?} }^{2} }{?} }^{?} }{?} \times \frac{?}{?} }^{2} }^{?}$
ok

Answer 2

Answer:

Step-by-step explanation:

8taps = 27min

1 tap = 8×27=216min to fill tank

=: 6taps = 216/6

= 36

Therefore 6 taps take 36 min to fill the tank.