Math, asked by anitasahu51084, 3 months ago

8 taps can fill a tank in 48 minutes. If two taps go out of order, how long will the remaining taps take to fill the tank?​

Answers

Answered by eshwarsai902
2

Answer:36 minutes.

Step-by-step explanation:

Given that,

8 taps of the same size fill a tank in 27 minutes.

So, 1 tap can fill the tank in 8×27=216 minutes

If two taps go out of order, then the remaining taps =8−2=6

Therefore, Time taken  by 6 taps to fill the tank =  

6

216

​  

=36 minutes.

Answered by neetuverma9451267971
0

Answer:

80 minutes will be the answer

Step-by-step explanation:

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