8 taps can fill a tank in 48 minutes. If two taps go out of order, how long will the remaining taps take to fill the tank?
Answers
Answered by
2
Answer:36 minutes.
Step-by-step explanation:
Given that,
8 taps of the same size fill a tank in 27 minutes.
So, 1 tap can fill the tank in 8×27=216 minutes
If two taps go out of order, then the remaining taps =8−2=6
Therefore, Time taken by 6 taps to fill the tank =
6
216
=36 minutes.
Answered by
0
Answer:
80 minutes will be the answer
Step-by-step explanation:
please mark me as brainiest
Similar questions