8 taps having the same rate of flow ,fill a tank in 27 min .if two taps go out of order how long will the remaining taps take to fill the tank.
Answers
Answered by
2
according to question
Time taken by 8 taps to fill the tank = 27 min
Thus
time taken by 1 tap to fill the tank = 27 / 8 min
As we know that
2 taps go out of order
thus number of taps working = 6
Thus
Time taken by 6 taps to fill the tank = 27 / 8 * 6
= 81/4 min
Time taken by 8 taps to fill the tank = 27 min
Thus
time taken by 1 tap to fill the tank = 27 / 8 min
As we know that
2 taps go out of order
thus number of taps working = 6
Thus
Time taken by 6 taps to fill the tank = 27 / 8 * 6
= 81/4 min
Answered by
2
Answer:
36 mins
Step-by-step explanation:
8 taps= 27 min
1 tap = 27 x 8 min= 216 min
6 taps = 216/6 min= 36 min
The remaining 6 taps will take 36 minutes to fill the same tank
Similar questions