Question

8
$x {}^{2}$
+
$2 \sqrt{3} x - 9 = 0$

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Answer 1

Answer:

(-3√3)/4 or x = √3/2

Step-by-step explanation:

8x² + 2√3x - 9 = 0

Split the middle term( term with x ) in such a manner so that the product of those parts will be equal to the product of coefficient of x^2 and constant.

Here,

2√3 = 6√3 - 4√3

= > 8x² + ( 6√3 - 4√3 )x - 9 = 0

= > 8x² + 6√3x - 4√3x - 9 = 0

= > 2x( 4x + 3√3 ) - √3( 2x + 3√3 ) = 0

= > ( 4x + 3√3 ) ( 2x - √3 ) = 0

= > 4x + 3√3 or 2x - √3 = 0

= > x = (-3√3)/4 or x = √3/2