Question

8 th term of AP is 32,find the sum of the 15th term.​

Answer 1

Answer:

let rst

term of this A.P. be a , commom difference be d

Now, nth term of A.P. is given by:

a+(n-1)d

so, its 8th term = a+(8-1)d = a+7d

but 8th term of A.P. is 32

so, a+7d = 32 ...(1)

similarly, 12th term = a+(12-1)d = a+11d = 52

so, a+11d= 52 ....(2)

Subtracting eq (1) from (2),

a+11d - (a+7d) = 52 - 32

=》4d = 20

=》d= 5

putting the value of d in (1),

a+7d = a+7×5 = 32

=》a+35 = 32

=》 a = -3

Now, a = -3 and d = 5

so, second term of A.P. = a+ d = -3+5 = 2

similarly 3rd term = a+2d = -3 + 5×2 = 7

so, Required A.P. is : -3,2,7,12,17

Answer 2

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