8) The absolute value of -41 is
9) (11 x (-6)) * (-30) - 11 x [(-6)
0 + 67 -
10)
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Using second law of motion, derive the relation between force and acceleration. A bullet of 10 gm strikes a sand bag at a
speed of 10³m/a and gets embedded after travelling 5cm. calculate:(i)the resistive force exerted by the sand on the bullet?, (ii) the time taken by the bullet to come to rest?
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Answer:
Step-by-step explanation:
8) 41
9) [11x(-6)] x (-30)-11 x (-6)
= {[-66] x (-30)} - 11 x -6
= (1980) -11 x -6
= 1980 - 66
= 1914
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