8. The ages of Seeta and Geeta are in the ratio 5:2. After 3 years, Seeta will be twice as old as Geeta. Find
(Note : Solve the problem in the next page.)
their present ages.
Answers
Answer:
Step-by-step explanation:
The ratio of the ages of Seeta and Geeta is 2 : 7.
Let the rational between the ages of Seeta and Geeta be x
Thus the ages of Seeta 2x and Geeta 7x
After 6 years, the ratio of their ages will be 1:2.
After 6 years their ages will be Seeta 2x + 6 and Geeta 7x + 6. Their ratio
2x + 6/7x + 6 = 1/2
Cross multiplication
1 (7x + 6) = 2 (2x + 6)
7x + 6 = 4x + 12
7x - 4x = 12 - 6
3x = 6
x = 6/3
x = 2
The rational between ages of Seeta and Geeta is 2, therefore the ages if Seeta and Geeta are
Seeta's age 2x = 2 × 2 = 4 years
Geeta's age 7x = 7 × 2 = 14 years.
The difference in ages of Seeta and Geeta's is
14 years - 4 years = 10 years
Geeta is older than Seeta by 10years
Answer:
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