Question

8. The ages of Seeta and Geeta are in the ratio 5:2. After 3 years, Seeta will be twice as old as Geeta. Find
(Note : Solve the problem in the next page.)
their present ages.​

Answer 1

Answer:

Step-by-step explanation:

The ratio of the ages of Seeta and Geeta is 2 : 7.

Let the rational between the ages of Seeta and Geeta be x

Thus the ages of Seeta 2x and Geeta 7x

After 6 years, the ratio of their ages will be 1:2.

After 6 years their ages will be Seeta 2x + 6 and Geeta 7x + 6. Their ratio

2x + 6/7x + 6 = 1/2

Cross multiplication

1 (7x + 6) = 2 (2x + 6)

7x + 6 = 4x + 12

7x - 4x = 12 - 6

3x = 6

x = 6/3

x = 2

The rational between ages of Seeta and Geeta is 2, therefore the ages if Seeta and Geeta are

Seeta's age 2x = 2 × 2 = 4 years

Geeta's age 7x = 7 × 2 = 14 years.

The difference in ages of Seeta and Geeta's is

14 years - 4 years = 10 years

Geeta is older than Seeta by 10years

Answer 2

Answer:

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