Question

8) The altitudes of an equilateral triangle, having the length of its side 10 cm is
a) 10 cm
b) 52cm
c) 5 cm
d) 5.3 cm​

Answer 1

Answer:

a) 10cm

Step-by-step explanation:

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Answer 2

Answer:

$\sqrt{75}$

Step-by-step explanation:

Let the triangle be ABC

Draw AD perpendicular to BC

AB=10cm

BD=10cm/2=5cm

By Pythagoras' Theorem,

AB^2=BD^2+AD^2

100=25+AD^2

75=AD^2

AD=75^(1/2)

AD=8.6602cm