Question

8. The area of a rectangle is 24 sq.cm. If the length of the rectangle is 8 cm find its breadth
and cost of fencing it at the rate of Rs. 2 per metre.​

Answer 1

Given:

• Area of rectangle = 24 m²
• Length of rectangle = 8 m

To find:

• Breadth of the rectangle
• Cost of fencing the rectangular plot of land at ₹2 per m.

Solution:

As we have to find the cost of fencing the rectangular plot of land, i.e. the perimeter of the rectangle, first its necessary to know the breadth of the rectangle.

We know that,

$\boxed {\mathfrak {\orange {Area\ of\ rectangle = l \times b}}}$

24 = 8b

$\sf \dfrac {24}{8} = b$

$\bigstar {\bf {\pink {3\ m = breadth}}}$

Now,

$\boxed {\mathfrak {\blue {Perimeter\ of\ rectangle = 2(l+b)}}}$

Perimeter = 2(8+3)

Perimeter = 2×11

$\bigstar {\bf {\red {Perimeter = 22\ m}}}$

Cost of fencing 1 m plot of land = ₹2

Cost of fencing 22 m plot of land = 2×22

= ₹44

Cost of fencing:

Cost of fencing the rectangular plot of land is ₹44.

Answer 2

Given Question :-

• The area of a rectangle is 24 sq.cm. If the length of the rectangle is 8 cm find its breadth and cost of fencing it at the rate of Rs. 2 per metre.

$\bf \:\huge \red{AηsωeR }$

$\large\sf{\underbrace{\underline{To\ find:-}}}$

Breadth of rectangle.

Cost of fencing at the rate of Rs 2 per metre.

$\begin{gathered}\begin{gathered}\bf Given -  \begin{cases} &\sf{area \: of \: rectangle \: = {24 \: cm}^{2} } \\ &\sf{length \: of \: rectangle \: = 8 \: cm} \end{cases}\end{gathered}\end{gathered}$

$\large\sf{\underbrace{\underline{Formula\ to\ be\ used:-}}}$

$\boxed{ \green{\bf \: Area\:of\:Rectangle=Length × Breadth}}$

$\boxed{ \red{ \tt \: Perimeter\:of\:Rectangle=2(Length + Breadth)}}$

$\large\underline\purple{\bold{Solution :- }}$

$\begin{gathered}\bf\red{We \: know,}\end{gathered}$

$\tt \: Area\:of\:Rectangle=Length × Breadth$

$: \implies \tt \: 24 = 8 \times Breadth$

$: \implies \tt \: Breadth = \dfrac{24}{8}$

$: \implies \tt \: \boxed{ \blue{ \bf \: Breadth = 3 \: cm}}$

$\begin{gathered}\bf\red{We \: know,}\end{gathered}$

$: \implies \tt \: Perimeter\ =\ 2(length\ +\ breadth)$

$\implies \tt \: Perimeter\ =\ 2(8 + 3)$

$\implies \tt \: Perimeter\ =\ 2 \times 11$

$\implies \tt \: \boxed{ \pink{ \bf \: Perimeter\ =\ 22 \: cm}}$

$\begin{gathered}\bf\red{Now,}\end{gathered}$

$\tt\implies \:Cost \: of \: fencing = 22 \times \dfrac{2}{100} = 0.44 \: rupees$