Question

8. The area of a rectangle whose perimeter is 130 cm and breadth 30 cm is
a) 2050 sq. cm b) 1050 sq. cm c) 550 sq. cm
d) 1150 sq. cm ​

Answer 1

Given :-

• Perimeter of the rectangle = 130 cm

• Breadth of the rectangle = 30 cm

To Find :-

• Area of the rectangle.

Solution :-

Perimeter of the rectangle :-

$:\implies\sf{130=2(l+b)}$

$:\implies\sf{130=2(l+30)}$

$:\implies\sf{130=2l+60}$

$:\implies\sf{2l=130-60}$

$:\implies\sf{2l=70}$

$:\implies\sf{l=\dfrac{70}{2} }$

$\sf:\implies \underline{\boxed{\pink{\mathfrak{l = 35\:cm}}}}$

∴ Length of the rectangle = 35 cm

Now,

Area of the rectangle :-

$:\implies\sf{Area=l\times b}$

$:\implies\sf{Area =35\times 30}$

$\sf:\implies \underline{\boxed{\pink{\mathfrak{Area= 1050\:cm}}}}$

∴ Area of the rectangle = 1050 cm.